Question

Two point charges 2 mue C -3 mue C and are placed 2m part. what is the electric field at the mid point?​

Answer 1

Answer:

At mid point the 2μ charge will act in positive x - axis and -3μ will also act in positive x - axis

So,

Let Electric Field due to 2μ charge be E1

and Electric Field due to -3μ charge be E2

So Net Electric Field (E) will be,

E = E1 + E2

Now,

E1 = 2μ/4π∈(1)²

E1 = 9 * 10^(9) * 2 * 10^(-6)

E1 = 18 * 10^(3) N/C

and

E2 = 3μ/4π∈(1)²

E2 = 9 * 10^(9) * 3 * 10^(-6)

E2 = 27 * 10^(3) N/C

So Net Electric Field Will Be

E = 27*10^(3) + 18*10(3)

E = 45*10^(3)

Thanks :)