Two point charges 20×10^-6c and -4×10^-6c are separated by a of 50 cm in air.
1)find the point on the line joining the charges, where electric potential is zero.
2) also find the electrostatic potential energy of the system.
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Answer:
=50/20×10^-6÷4×10^-6±1
50/5-1
=12.5
Explanation:
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