Question

Two point charges 3nC and -3nC are placed at two corners A and B of an equilateral triangle of side 0.1m. Find the resultant electric field at C. ​

Answer 1

Answer :

E'=27*10² N/C

Used Formula :

Electric field = kq/r²

Where,

q= charge on point charge

r= distance between point and point charge

Units Conversion :

q= 3nC = 3* 10^-9C

r = 0.1m

Note :

i)Angle between them is 120°

ii) Electric field is a vector quantity (direction and magnitude dependent). So resultant Electric field should be calculated by taking vector methods.