Question

Two point charges 4 micro C and 10 micro C are placed at 20cm distance.The electrostatic potential energy of the system is​

Answer 1

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q₁ = 4×10⁻⁶ C

q₂ = 10×10⁻⁶ C

r = 20cm = 0.2m

Electrostatic potential = U

U = -kq₁q₂/r

U = -9×10⁹×4×10⁻⁶×10×10⁻⁶ / 0.2

U = -360×10⁹⁻¹² / 0.2

U = -3600×10⁻³ / 2

U = -1800×10⁻³

U = -1.8J

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