Question

Two point charges 4 microcoulomb and 1 microcoulomb are separated by a distance of 2 metre in air. find the point on the line joining the charges at which net electric field of the system is zero.​

Answer 1

4 micro culoumb

1 micro culoumb

Distance of air =2m

4x1/2=0

2=0

Answer 2

Answer:

Distance from charge Q1= 1.33m

Distance from charge Q2= 0.67m

Explanation:

Given charges:-

Q1=4 microcoulomb

Q2=1 microcoulomb.

Distance between Q1 and Q2 =2 m

Find:- the point on the line joining the charges at which net electric field of the system is zero.

So let the required point is P ,at the distance x m from charge Q1 and distance (2-x) m from charge Q2.

The electric field between Q1 and Point P is E1 =1/4π€o Q1/x^2

The electric field between Q2 and point P is E2= 1/4π€o Q2/(2-x) ^2

For the E is 0 so

E1=E2