two point charges 4 microcoulomb and 10 microcoulomb are separated by a distance 0.9 CM in air find the position of point where resistant in intensity is zero?
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Explanation:
Let the two charges placed at two points of line AB as A and B whose distance is 20 cm and O is the mid point of the line AB
Distance between the two charges , AB=20 cm
∴AO=OB
Net elctric at O=E
Electric field at point O caused by +5\mu C charge,
E
1
=
4πε
0
(AO)
2
5×10
−6
=
4πε
0
(10×10
−2
)
2
5×10
−6
N/C toward +5μC
where,
ε
0
=Permittivity of free space
4πε
1
=9×10
9
Nm
2
C
−2
Magnitude of electric field at point O cause by +10\mu C charge,
E
1
=
4πε
0
(AO)
2
10×10
−6
=
4πε
0
(10×10
−2
)
2
10×10
−6
N/C towards +10μC
∴E=E
1
+E
2
=
(10×10
−2
)
2
9×10
9
×15×10
−6
=13.5×10
6
N/C towards +5μC
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