Two point charges 4 microcoulomb and minus 2 microcoulomb are separated by a distance of 1m in air at what point on the line joining the charges is the electric potential zero
Answers
Assuming that negative charge is placed to the left of the positive one.
The potential will be zero to the left of negative charge.
Electric potential at a point=k×q÷r.
Let the potential be zero at a distance x from the negative charge.
The net potential at the point= -k×2÷x +k×4÷(1+x)
0 = -2k(1+x)+4kx
2kx=2k
x=1m
The electric potential is zero at a distance of 1m to the left of negative charge
Explanation:
let the distance be x m
r=1m
Q=4micro coulomb
q=-2 micro coulomb
VQ+Vq=0
kQ/x+kq/(r-x) = 0
k4/x -k2/(1-x)= 0
k4/x=k2/(1-x)
4(1-x) = 2x
4-4x=2x
x=2/3=0.66 m will be the point where line joining will be 0