Question

Two point charges +4q and – q are placed 30 cm apart. At what point on the line joining them the electric potential is zero?

Answer 1

Answer:

Thus the point will be 30-x away from charge 4q. For electric field intensity to be equal, electric field due to two points should be equal. Thus this point will be 10 cm from +q and 30-10 = 20 cm from charge +4q.

Explanation:

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