two point charges +8q,_2qare located at 2 ends seprated by a distance of 3 meter .find the location of the point where the net electric field due to there 2 charges ix zero
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The electric field due to +8q is towards left and that due to −2q is towards right.
Electric field at a general point x=d (<0) is E=4πϵ01(−d28q+(L−d)22q)
If E=0, then d28q=(L−d)22q⇒(L−d)2d2=4
But, if d<0, then ∣d∣<∣L−d∣. Hence, no solution exists.
Consider the region between x=0 and x=L
The electric field due to +8q is towards right, and that due to −2q is towards right.
Hence, there is no point in(0,L) with zero electric field.
Consider the region between x=L and x=+∞
The electric field due to +8q is towards right and −2q is towards left.
Electric field at a general point x=d(>L) is given by E=4πϵ01(+d28q−(d−L)2
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