Physics, asked by tamizhselvan1312, 7 hours ago

two point charges +9yc and +3yc are separated by distance of 2.25cm the force between the charges is​

Answers

Answered by Anonymous
3

Explanation:

Apply coulomb's law

Distance = 2.25 cm

= 0.0225 m

k = 8.99 × 10 9 N ⋅ m^2 /C^2

F = k q1q2/r^2

.

F = 8.99 × 10^9 * (9 * 3) / (0.0225)^2

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