Question

Two point charges A and B, having charges +Q and -Q respectively, are placed at certain distance apart and force acting between them is F. If 50% charge of A is transferred to B, then force between the charges becomes

Answer 1

Answer:

Correct option is

B

169F

F=r2KQ2

If 25% of charge of A transferred to B then 

qA=Q−4Q=43Q and qB=−Q+4Q=4−3Q

F1=r2kqAqB

F1=r2k(43Q)2

F1=169r2kQ

⟹F1=169F

Explanation:

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Answer 2

I hope it's help uh..

Mark itz brainlist plz