Two point charges are located on the x-axis.The first is a charge +Q at x=-a .The second is unknown charge located at x=+3 a.The net electric field these charges produce at the origin has magnitude of (2kQ)/(a^(2)) .What are the possible value(s) of the unknown charge? (A) -9Q (B) +9Q (C) +27Q (D) +8Q
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a -9Q is the answer....
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The possible value of the unknown charge is equal to +27 q
Option c
Explanation:
- Let us first considered about the first charge. The magnitude of the charge is equal to + q and the the distance from the axis is equal to a. Hence the electric field due to the first charge is equal to, -kQ/a²
- Let us consider the second charge to be of magnitude x,
- Show the electric field due to the second charge is equal to Kx/9a²
- The total electric field is given to be 2kQ/a²
- From our calculations it is Kx/9a² - Kq/a²= k/a²x( x/9 - q)
- Hence so comparing the above two equation ,
- x/9 - q = 2q
Or x= 27q
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What is the kinematics - Brainly.in
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