Question

Two point charges are separated by a distance
R in air repel each other by a force F. One
of the charges is doubled and the other is
made one-fourth. For what new separation
between them will the force remains same​

Answer 1

Answer:

F1=k*q 1*q2/(d/2)^2. =4*k*q1*q2/d^2 ... What will be the effect on force if distance between two point charges is increased by 10%? ... If r is halved. therefore new distance, r1 = r/2.