Question

Two point charges are separated by some distance in vacuum. When the space between the charge is filled by some dielectric , the force between the charge ............

Answer 1

Answer:

t two points charges `q_(1), q_(2)` be placed in a medium of dielectric constant `K` at separation `r`.

`F_(1) = (1)/(4 pi in_(0)) (q_(1) q_(2))/(K r^(2))` (i)

If we want that charges should be placed in vacuum to have the same force as in medium, we have to increase separation between charges.

`F_(1) = (1)/(4 pi in_(0)) (q_(1) q_(2))/(r'^(2))` .....(ii)

Since `F_(1) = F_(2)`

`r' = r sqrt(K)`

When the slab of thickness `t` is placed between charges , `t` is equivalent to `t sqrt(K)` of vaccum.