Question

Two point charges each of 5 microcoulomb but opposite in sign are placed 4 cm apart. Calculate the electric field intensity at a point 4 cm from the midpoint of the axial line of the dipole. Answer please!!

Answer 1

Answer:The electric field intensity is 0.562\times10^{8}\ N.

Explanation:Given that,

Charge

Distance

The electric field intensity at a point 4 cm away from the midpoint of the axial line is

The electric field intensity on the axial line define as:

Here, p = ql

Hence, The electric field intensity is .