Question

Two point charges each of 5 microcoulomb but opposite inside are placed 4 centimetre apart calculate the electric field intensity at a point 4 cm away from the midpoint of the axial line

Answer 1

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Answer 2

Answer:

The electric field intensity is $0.562\times10^{8}\ N$.

Explanation:

Given that,

Charge $q=5\times10^{-6}\ coulomb$

Distance $r= 4\times10^{-2}\ meter$

The electric field intensity at a point 4 cm away from the midpoint of the axial line is

The electric field intensity on the axial line define as:

$E_{axial}=\dfrac{k2p}{r^3}$

Here, p = ql

$E_{axial}=\dfrac{9\times10^{9}\times2\times5\times10^{-6}\times4\times10^{-2}}{(4\times10^{-2})^3}$

$E_{axial}=0.562\times10^{8}\ N$

Hence, The electric field intensity is $0.562\times10^{8}\ N$.