two point charges each of charge q=4 C are placed at distance a=b= 2 cm from the origin as shown what is the angle Subtended by the resultant electric field at point P with you axis
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Given that:
Q
1
=2 μC ans Q
2
=1 μC
We know that:
E∝
d
2
Q
⇒
E
2
E
1
=
(2cm)
2
2μ
×
1μ
(1cm)
2
=
2
1
⇒E
2
=2E
1
As
E
1
is directed along +ve x-axis and
E
2
along +ve y-axis, angle made by their resultant
E
with +ve x-axis is given by tanθ=
E
1
E
2
=2
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