Question

Two point charges having equal charges separated by 1m distance experience a force of 0.8N. then the force experienced by them when placed in a medium of dielectric constant 80 at the same distance is__________________

Answer 1

Answer:

$\large\boxed{\sf{0.01\;N}}$

Explanation:

Given that,

Two point charges having equal charges separated by 1m distance experience a force of 0.8N.

To find the force experienced by them when placed in a medium of dielectric constant 80 at the same distance is.

Let the dielectric constant is k

Also, the force exerted without dielectric constant is f.

Therefore, we have,

=> f = 0.8 N

Now, we know that,

When a dielectric constant 'k' is placed in a medium, then the force exerted simply becomes f/k.

Therefore, new force , F = f/k

Substituting the respective values, we get,

=> F = 0.8/80

=> F = 8/800

=> F = 1/100

=> F = 0.01 N

Hence, the new force will be of 0.01 N magnitude.