Physics, asked by gunjankumar54901, 1 year ago

Two point charges of 1.0 microcoulomb and -0.25 microcoloumb are placed in air at a distance of

Answers

Answered by empathictruro
0

Answer:

Explanation:

Assuming that we are required to find the force of attraction between two particles , let us consider the charge of two particles to be q1 and q2 respectively and are placed at a distance of d apart, the force of attraction between the two particles is given by the formula

Force F is proportional to the product of the charges and inversely proportional to the square of the distance between the particle, the proportionality symbol is replaced by constant k.

F=(k×g1×g2)÷d^2

In the above problem the value of charges are given if the distance is known the value of force can be found out.

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