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Two point charges of +1.0 my C are kept stationary 2m apart.How much work is needed to be done to bring them 1m apart ?

1) 4.5 mJ

2) 9 mJ

3) 45 mJ

4) 90 mJ

## Answers

Answered by

69

4.5 mJ is the right answer

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Answered by

59

**Answer:**

The work done is 4.5 mJ.

**1 is correct option**

**Explanation:**

**Given that,**

Given that,

Charges

Distance d = 2 m

The potential energy is,

**The work done is equal to the change in potential energy.**

Where, =Initial potential energy

=final potential energy

The initial potential energy is

The final potential energy is

Now,work done = change in potential energy

Put the value into the formula

**Hence, The work done is 4.5 mJ.**

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