Question

Two point charges of +1.0 x 10-6C and -1.0 x 10-60
are at a distance 2.0 cm apart from each other. This
electric dipole is situated in a uniform electric field of
1.0 x 105 V-m-1. What will be the maximum torque
acting on it due to the field? What will be the work
done for rotating it through 180° from the equilibrium
position?

Answer 1

Explanation:

ANSWER

The volume of aluminum ball is

V=

3

4

πr

3

=

3

4

π(0.5

3

)

V=0.5266cm

3

The force acting on the ball is

1)downward force due to self weight

2)upthrust due to bouyant force

Bouyant force BF=weight of water displaced

=ρ

w

g(0.5266/2)

=1×g×0.2633

=0.2633g

Self weight W= ρ

al

g×0.5266

= 2.7×g×0.5266

= 1.4218g

Net weight F = W−BF= 1.4218g−.2633g

F = 1.1585g

Now, weight per unit length of the rod =

x+y

4.4g

Taking moment on each side

1.1585g×x +

x+y

4.4g

.x.

2

x

=

x+y

4.4g

.y.

2

y

1.1585g×x =

2(x+y)

4.4g

(y

2

−x

2

)

1.1585g×x = 2.2g(y−x)

3.3585x=2.2y

x

y

=1.52≅1.5

Answer 2

Answer:

Explanation:

Here is your answer

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