Question

two point charges of +1 microcoulomb and -1 microcoulomb are kept at a distance of 2cm and they form an electric dipole . this dipole is situated in a uniform electric field of 1*10^5 Newton per coulomb the dipole moment vector P making an angle of 30° with the field calculate the magnitude of electric dipole moment and torque acting on the dipole then what should be the torque maximum how much

Answer 1

Answer:

100000000000

Explanation:

₹₹₹₹₹$₹₹₹₹₹₹₹₹₹₹₹₹₹₹

Answer 2

Given:

q1 = +1 μC = + $1 \times 10^{-6}$ C

q2 = -1 μC = - $1 \times 10^{-6}$ C

r = 2 cm = $2 \times 10^{-2}$ m

E = $1 \times 10^5$ Newton per coulomb

θ = 30°

To find:

1) p =?

2) τ =?

Explanation:

1)

The electric dipole moment for a pair of equal & opposite charges is the magnitude of the charges multiplied by the distance between the two.

∴p = q×d

p = $1 \times 10^{-6} \times 2 \times 10^{-2$

p =  $2 \times 10^{-8}$

p = 0.2 μC

2)

We know that

τ =  qEsinθ

τ = $1 \times 10^{-6}$ $\times 2 \times 10^{-2}$ × sin 30°

τ = $1 \times 10^{-8}$

τ = 0.1 Nm