Two point charges of + 10 C and + 20 uC are
placed in free space 2 cm apart. Find the electric
potential at the middle point of the line joining the
two charges
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Explanation:
V¹ = 9 x 10⁹ x (10)/ 0.01 = 9 x 10¹²v
V² = 9 x 10⁹ x (20)/0.01 = 18 x 10¹²v
V = V¹ + V²
= 27 x 10¹²v
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