Question

Two point charges of 10C each are kept at distance of 3 m in vacuum. Calculate their electrostatic potential energy.​

Answer 1

Given,

q1 =q2 = 10 C,

Distance between the charges = 3m

We know,

The electric Potential energy of a system of charges is the work that has been done (=charge*potential) in bringing those charges from infinity  to near each other to form the system.

U = $\frac{1}{4\pi\epsilon_0}\frac{q1q2}{r}$

= $\frac{9*10^{9}*10*10}{3}$

= $3*10^{11} J$

Thus, the electrostatic potential energy is $3*10^{11} J$.

Answer 2

ISC (Science) Class 12 - Physics (Theory)

$\large{\underline{\boxed{\tt Answer}}}$

3×10^11 j (Joules)

$\large{\underline{\boxed{\tt Explanation}}}$

$\large{\underline{\boxed{\tt Given Problem}}}$

Two point charges of 10C each are kept at distance of 3 m in vacuum. Calculate their electrostatic potential energy.​

Solution:

$\large{\underline{\boxed{\tt To Calculate}}}$

Potential energy.​

---------------------------------

The electric Potential energy = charge*potential

$\dfrac{1}{4\pi\epsilon_{0}}$ × $\dfrac{q_{1} q_{2}}{r}$

$\dfrac{9 \: \times \: {10}^{9} \: \times \: 10 \: \times10 }{3}$

Hence,

$\huge\boxed{[tex]3 \: \times \: {10}^{11}$ J j (Joules)}[/tex]