Question

two point charges of 10C each,are placed 3 metres apart. Calculate the electric potential energy of the system.
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Answer 1

Answer:

Given,

q1 =q2 = 10 C,

Distance between the charges = 3m

We know,

The electric Potential energy of a system of charges is the work that has been done (=charge*potential) in bringing those charges from infinity to near each other to form the system.

U = \frac{1}{4\pi\epsilon_0}\frac{q1q2}{r}

4πϵ

0

1

r

q1q2

= \frac{9*10^{9}*10*10}{3}

3

9∗10

9

∗10∗10

= 3*10^{11} J3∗10

11

J

Thus, the electrostatic potential energy is 3*10^{11} J3∗10

11

J .