Question

Two point charges of 16 microcoulomb and 64 microcoulomb are placed 3m apart in air. find the position of a point where the intensity due to two charges will be equal.​

Answer 1

Answer:

At a distance of 24 cm from the negative charge and 27 cm from the positive charge, the resultant electric field is zero.

Explanation:

• Because both charges have the same sign, which implies they act in opposite directions, the zero electric field point cannot exist between them; it must occur on one of the sides. Consider the point P, where the electric field is zero and the negative charge is x distance away.
• As a result, the diagram is shown below.
• Allow point A to have a positive charge of +16 C and point B to have a negative charge of 64 C. The distance between A and B is 3 cm.
• Consider a location P that is x distance from B. P is the zero point of the electric field.
• Thus, the electric field acting on point P due to the positive charge at A is,  
• Similarly, the electric field acting on point P due to the negative charge at B is,
• The resultant electric field should be zero at P, so,
• Taking square root on both the sides,
• Thus, the point P should be at a distance of 24 cm from the negative charge and (24+3) cm distance from the positive charge.
• So the distance between PA is 27 cm and PB is 24 cm