Question

Two point charges of +16uC and -9uC are placed 8cm apart in air. Determine the position of the point at which the resultant electric field is zero.

Answer 1

Answer:

2.88 cm

Step by step explanation:

The givens are:

• The distance between the two charges is 8 cm
• The charges are 16u C and -9u C
• Resultant Electric potential 'V' = 0

$V=\frac{kq}{r}$

Let x be the distance at which V=0.

Therefore, $V_1+V_2=0$

$V_1=\frac{k(16u)}{8-x} \\ \\V_2=\frac{k(-9u)}{x}$

Hence,

$\frac{k(16u)}{8-x}=\frac{k(9u)}{x}\\ 16x=9(8-x)\\16x=72-9x\\25x=72\\x=2.88\:cm$