Two point charges of +16uc and _9uc are placed at 8cm apart determine the position of point at which resultant electric field is zero
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Answer:
4.6cm from 16uC
Explanation:
+16uC____________<8r>___________-9uC
when electric field is zero; from the formula --->
q/4π€r²= q/4π€r'²
(9×10^9 ×16×10^-6)/r² =(9×10^9×9×10 ^-6)/(0.08-r)²
144/r²=81/(0.08-r)²
12/r=9/(0.08-r)
9r=0.96-12r
21r=0.98
r=4.6cm from 16uC
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