Two point charges of 20uC and 80uC are placed 18cm apart. Find the position where electric field is zero.
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Answer:
at 6 cm from 20μc charge and in between 20μc charge and 80μc charge
Explanation:
- formula for electric field is kQ/R^2
- we have to consider a point (p) between 20μc to 80μc
- point p is (x) distance away from 20μc so point p is (18 - x) distance away form 80 μc
- now on point p there are 2 vectors and both are in opposite direction to each other.
- one vector on point p ( electric field on p due to 20 μc ) = k 20/x^2
- another vector on point p ( electric field due to 80 μc ) = k80/(18-x)^2
- so E net on point p = k20/x^2 - k80/(18-x)^2
= k20(1/x^2 - 4/(18-x))
= k 20 ( 1/x - 2/(18-x))
- now we have to find a point where Enet = 0
- let that point be p
- so 0 = k 20 (1/x - 2(18-x)
0 = 1/x - 2/ (18-x)
1/x = 2/ (18-x)
18 - x = 2x
18 = 3x
x = 6 cm
- electric field is zero at 6 cm from 20μc charge and between 20μc charge and 80 μc charge......
hope it's useful................
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