Two point charges of +3 MUa C and +4 MUa C repel each other with a force of 10 N. If each is given an additional charge of - 6 MUa C, then the new force is.
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q1 = 3μC
q2 = 4μC
K= 9 x 10^9 Nm^2C^−2
F = (K x q1 x q2) / r^2
10 = ( 9 x 10^9 x 3 x 10^-6 x 4 x 10^-6) / r^2
then
r^2 = 0.108/10 = 0.0108------(i)
now -6μC add in every charge
now q1 = -3μC
q2 = -2μC
we don't take charge, -ve or +ve charge show repletion of attraction.
and here it show repletion
F = (K x q1 x q2) / r^2
F = (9 x 10^9 x 3 x 10^-6 x 2 x 10^-6) / 0.0108 from 1st equation
F = 5 N
this is your answer
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