Question

Two point charges of 30 microcoulomb and 40 microcoulomb are 20 cm apart from each other where will this electric field zero

Answer 1

Explanation:

It is because The electric field will be zero at 6.67 cm distance from 80 micro coulomb. Let the electric field will be zero at point O. Two point charges 20 micro coulomb and 80 micro coulomb are 10 cm apart at point A and B.Mark as Brainliest

Answer 2

" It seems this is what you are looking for"

Two point charges of 30μC and 40μC are 20 cm apart from each other . Where will be the electric field zero on the line joining the from 30μC charge ?

Answer:

The electric field will be zero, at the distance 9.27cm from point charge 30μC.

Explanation:

The first charge q₁= 30μC = 30 ×10⁻⁶C

The second  charge q₂ = 40μC = 40 ×10⁻⁶C

The distance between the two charges d= 20cm= 0.2m

Consider that a point O between two charges where the electric field will be zero. The distance between point O and charge q₁ is x and between point O and charge q₂ is 20-x.

Electric field at point O due to charge q₁ is E₁  $=\frac{Kq_{1}}{x^{2}}$                    ...........(2)        

Electric field at point O due to charge q₂ is E₂ $=\frac{Kq_{2}}{(0.2-x)^{2}}$                 ..........(1)

The electric field will be zero when E₁ = E₂:

$\frac{Kq_{1}}{(x)^{2}}=\frac{Kq_{2}}{(0.2-x)^{2}}$

$\frac{30*10^{-6}}{x^{2}} =\frac{40*10^{-6}}{(0.1-x)^{2}}$

$\frac{3}{x^{2}} =\frac{4}{(20-x)^{2}}$

Square root on both sides :-

$\frac{1.73}{x} =\frac{2}{(20-x)}$

$1.73(20-x)=2x$

$34.6-1.73x=2x$

$3.73x=34.6$

$x=9.27cm$

Therefore, at the distance 9.27cm from the charge 30μC the electric field will be zero.