Two point charges of +4micro coulomb and + 9 micro coloumb are placed 50 cm apart What should be the value of third charge Q° which should be placed between them so that the system is in equilibrium.
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Answer:
15.38 cm
Explanation:
Force on Q charge from both charges should be same
F1=F2
∴(Kq1Q)/r = (Kq2Q)/50 - r
∴4/r = 9/(50-r)
∴200 - 4r =9r
∴13r= 200
∴ r =15.38 from 4 micro coulomb charge
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