two point charges of + 5 ucr so place that the experience a force of 8.0 10 - 3 and they are they move apart so that the force is now 2.0 10 - 3 and the distance between them is now
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Answer:
2r
Explanation:
let initial and final dist be r and R
initial; k[5]²/r²=8 * 10^-3
final; k[5]²/R²=2 * 10^-3
now you should divide both equations and then take square root to get relation between r and R
DO NOT TRY TO CALCULATE AND THEN SUBSTITUTE .....
these questions are to be solved like this only... if u try to calculate it will take many years....LOL
Thank you
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