Two-point charges of 6uC and 9uC
separated by 10 cm repel each other with
some force F. If a charge of - 4uC is
added with each of them, then the force
between them is 20 N. Calculate the
initial force exists between them before
adding the charge.
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Given:
Two-point charges of 6uC and 9uC separated by 10 cm repel each other with some force F. If a charge of - 4uC is added with each of them, then the force between them is 20 N.
To find:
Calculate the initial force exists between them before adding the charge.
Solution:
From given, we have,
q1 = 6μC
q2 = 9μC
d = 10 cm (distance between the charges)
Initial force = F
-4μC is added
Then, the new force = Fnew = 20 N
Using Coulomb's law, we have,
F = k q1×q2 / d²
F = k × 6μ × 9μ / 10²
Fnew = 20 = k × (6μ - 4μ) × (9μ - 4μ) / 10²
Fnew = k × 2μ × 5μ / 10²
Fnew / F = [ k × 2μ × 5μ / 10² ] / [ k × 6μ × 9μ / 10² ]
Fnew / F = (2 × 5) / (6 × 9)
F = 54/10 × Fnew = 54/10 × 20
∴ F = 108 N.
∴ The initial force is 108 N.
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