Question

Two point charges of 8 micro coulomb and - 4 micro coulomb are separated by a distance of 10cm in air. At what point on the line joining the two charges is the electric potential zero?

Answer 1

Answer:

5(√2 + 1) cm from -4μC  & 5(√2 + 3) cm  from 8μC

Explanation:

Two point charges of 8 micro coulomb and - 4 micro coulomb are separated by a distance of 10cm in air. At what point on the line joining the two charges is the electric potential zero?

As 1 charge is + Ve & another Charge is -ve

so point will lie out sides

Let say Point is on right side of -4μC at distance d cm

then (8 * 1 )/(10 + d)² = 4*1/d²

=> 2d² = (10 + d)²

=>(10+d)/d = √2

=> 10/d + 1 = √2

=> 10/d = √2 - 1

=> d = 10/(√2 - 1)

=> d = 5(√2 + 1)

5(√2 + 1) cm from -4μC  & 5(√2 + 3) cm  from 8μC