Two point charges of charge values Q and q are placed at distances x and
x/2 respectively from a third charge of charge value 4q, all charges being in the
same straight line. Calculate the magnitude and nature of charge Q, such that the
net force experienced by the charge q is zero.
Answers
Answered by
1
Answer:
Distance between 4q and q=
2
x
Distance between q and Q=x−
2
x
=
2
x
F
1
= Force between 4q and q
=k×
(
2
x
)
2
4q
2
=
x
2
16kq
2
F
1
= Force between q and Q
=k×
(
2
x
)
2
=
x
2
4kqQ
Net force =0
i.e, F
1
+F
2
=0
x
2
16kq
2
+
x
2
4kqQ
=0
x
2
16kq
2
=−
x
2
4kqQ
q=
4
−Q
i.e, Q=−4q
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