two point charges one of 100uC and another of -400uC, are kept 30cm apart. Find the point of zero potential on the line joining the two charges
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solution:-
Given ,
Two charge q100=+400μC
qp=100μC
q2=400μC
d=30cm=.3m
Let point P (where, f1μC=0) is at distance r from q1 [ref. image]
F1+F2=0
kr2q1×qp−k(.3−r)2q1qp=0
r2q1=(∗.−2)2q2
(r.3−r)2=q1q2=14=4
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