Question

two point charges placed at a distance r in air exert a force F on each other​

Answer 1

Answer:

Answer:Plzz. Share the diagram as your is not clear

Answer 2

Answer:

F (air) = (1/4 pi eo) [qQ/r^2] 

F(medium) = (1/4 pi eo*k) [qQ/R^2] 

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given> F(medium) = F(air) 

(1/4 pi eo*k) [qQ/R^2] = (1/4 pi eo) [qQ/r^2] 

(1/k) [1/R^2] = [1/r^2] 

kR^2 = r^2 

R^2 = r^2/k 

R = r/ [rootk] 

Explanation: