Two point charges placed at a distance r in air exert a force F on each other.
At what distance will these charges experience the same force F in a medium
of dielectric constant K?
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Answer:
Correct option is
C
k
r
Two point charge placed at a certain distance =r
force =F
dielectric constant =k
Let, two point charges q
1
and q
2
are separated r distance from each other.
Then, force experienced between then,
F=
4πϵ
0
r
2
q
1
q
2
Put, F=
4πϵ
0
r
2
q
1
q
2
∴
4πϵ
0
r
2
4q
1
q
2
=
k(4πϵ
0
r
2
)
q
1
q
2
⇒
r
2
1
=
4r
2
h
1
⇒
r
2
1
=
kr
2
1
taking square root both sides
r
1
−
k
r
1
1
or, r
1
=
k
r
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