Physics, asked by 9764670, 1 year ago

.Two point charges placed at a distances of 20 cm in air repel each other with a certain force. When a dielectric slab of thickness 8 cm and dielectric constant K is introduced between these point charges, force of interaction becomes half of it’s previous value. Then K is approximately

Answers

Answered by monusinghal
1
I think value of k will be 2
Answered by Rinisha08
5

Value of K (dielectric constant ) is 4




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