Two point charges q and 10q repel each other with a force of 3.6 ×10^-5 N when they are 0.02 metres apart. Find the charges.
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Force between 2 point charges is given by
F = kq₁q₂/r²
3.6 × 10^-5 N = 9 × 10^9 Nm^2/C^2 × q × 10q / (0.02 m)^2
q = sqrt((3.6 × 10^-5 × (0.02)^2) / (9 × 10^9 × 10)) C = 4 × 10^-10 C
∴ Charges are
q = 4 × 10^-10 C
10q = 10 × 4 × 10^-10 C = 4 × 10^-9 C
F = kq₁q₂/r²
3.6 × 10^-5 N = 9 × 10^9 Nm^2/C^2 × q × 10q / (0.02 m)^2
q = sqrt((3.6 × 10^-5 × (0.02)^2) / (9 × 10^9 × 10)) C = 4 × 10^-10 C
∴ Charges are
q = 4 × 10^-10 C
10q = 10 × 4 × 10^-10 C = 4 × 10^-9 C
rhearocx:
Hey, the answer given at the back of the book is 0.4×10^(-9) C & 0.4×10^(-9) C
&*
and*
If one is 0.4 × 10^-9 C then other should be 0.4 × 10^-8 C because one is q and other is 10q
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Hey mate plzz refer to the attachment
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