Two point charges q and 9q are separated by a distance of 10a.find the point on the line joining the two charges where electric field is zero
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in the following question let some point X where electric field due to both charges is in equilibrium
field due to q on point X = field due to 9q on point X
kq/X^2 =k(9q)/(10a-X)^2
10a-X/X=3
10a-X=3X
10a=4x
5a/2=X
hence the electric field must be zero at a point 5a/2 away from q
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