Question

Two point charges q and – q are located at (0, 0, – a) and (0, 0, a) respectively.
(a) Depict the equipotential surfaces due to this arrangement.
(b) Find the amount of work done in moving a small test charge q0 from point
(l, 0, 0) to (0, 0, 0).​

Answer 1

Answer:

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Explanation:

(a) Zero at both the points  Charge − q is located at (0, 0, − a) and charge + q is located at (0, 0, a). Hence, they form a dipole. Point (0, 0, z) is on the axis of this dipole and point (x, y, 0) is normal to the axis of the dipole. Hence, electrostatic potential at point (x, y, 0) is zero. Electrostatic potential at point (0, 0, z) is given by, Where,   = Permittivity of free space p = Dipole moment of the system of two charges = 2qa  (b) Distance r is much greater than half of the distance between the two charges.  Hence, the potential (V) at a distance r is inversely proportional to square of the distance (c) Zero  The answer does not change if the path of the test is not along the x-axis. A test charge is moved from point (5, 0, 0) to point (−7, 0, 0) along the x-axis. Electrostatic potential (V1) at point (5, 0, 0) is given by, Hence, no work is done in moving a small test charge from point (5, 0, 0) to point (−7, 0, 0) along the x-axis.  The answer does not change because work done by the electrostatic field in moving a test charge between the two points is independent of the path connecting the two points.Read more on Sarthaks.com - https://www.sarthaks.com/18264/two-charges-q-and-q-are-located-at-points-0-0-a-and-0-0-a-respectively