Question

Two point charges Q and q are placed 3m away from each other. The sum of the two charges is 20 micro coulomb and they repel each other with a force of 0.075 N . Find the two charges......​

Answer 1

Answer:

q+Q=20×10^-6.............(A)

Force =0.0075

Force=KqQ/r^2..........(1)

K=9×10^9

r=3m

substituting above value in equation (1)

0.075=9×10^9(qQ)/9

qQ=0.075×10^-9..............(B)

solve equationn (A) and (B)

to get q And Q.

this was concept behind que.

now you can solve two equation to get q and Q.

Thanks