Two point charges Q and q are placed at a distance X and x/2 from a third charge of 4q. Calculate the magnitude and nature of Q such that net force experienced by q is 0
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Two point charges Q and q are placed at a distance X and x/2 from a third charge of 4q.
see figure,
here it is clear that, if distance between Q and 4q is x then, distance between Q and q is (x - x/2) = x/2
a/c to question,
net force experienced by q = 0
force exerted by Q on q + force exerted by 4q on q = 0
or, kQq/(x/2)² (rightward) + kq(4q)/(x/2)²(leftward) = 0
or, kQq/(x/2)² (rightward) - 4kq²/(x/2)²(rightward) = 0
or, kQq/(x/2)² = 4kq²/(x/2)²
or, Q = 4q
hence, magnitude of Q = 4q and nature of Q is same as q or 4q.
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