Two point charges q1 = 0.2C and q2 = 0.4C placed 0.1m apart. Calculate the electric field at the mid point between the two charges
Answers
Answer:
Explanation:
Electric field, E = kq
r²
Electric field due to q₁ on q₂ will be : E₂,₁=k * 0.2/(5*10⁻²)²
Similarly, Electric field due to q₂ on q₁ qill be : E₁,₂= k * 0.4/(5*10⁻²)²
Since both are positive charges, they repel the point charge placed at their mid-point.
Therefore , net Electric field : E = E₁,₂ - E₂,₁
= k * (0.4-0.2)/25 * 10⁻⁴
= 9 * 10⁹ * 0.2 * 10⁴ / 25
= 18 * 10¹⁰ * 100/25
= 72 * 10¹⁰
= 7.2 * 10¹¹ N/C
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