Two point charges q1 = 400 micro coulomb and q2=100 micro coulomb are kept fixed 60 cm apart in vacuum find intensity of the electric field at mid point of the line joining q1 and q2
Answers
Given - q1 = 400 micro coulomb q2=100 micro coulomb
Distance - 60 cm
Find - Intensity of electric field at mid point of the two charges.
Solution - The formula to calculate intensity of electric field is as follows-
E = (1/4π€)(Q/r²)
In the formula, E refers to electric field, (1/4π€) can be written as 9*10^9, Q refers to charges. R² denotes the point at which Intensity of elctric field is to be calculated.
Since the intensity is to be calculated at mid point, the equation will be -
E = E1 - E2
R will be 30 cm(due to mid point) = 0.3 m.
Q1 for E1 - 400 microC = 4*10^-4 C
Q2 for E2 - 100 microC = 1*10^-4 C
E1 = 9*10^9*4*10^-4/(0.3)²
E1 = 4*10^7 NC
E2 = 9*10^9*1*10^-4/(0.3)²
E2 = 1*10^7 NC
Therefore, E = 4*10^7 - 1*10^7
E = 3*10^7 NC
Hence, intensity of electric field at mid point will be 3*10^7 NC.