Question

two point charges Q1 and Q2 and 3 metre away from each other the sum of two charges is 20 microcoulomb and they repel each other with a force of 0.075 Newton find the two charges​

Answer 1

$f = k \frac{q1 \: q2 \: }{ {r}^{2} } \\ 0.075 = 9 \times {10}^{9} \times \frac{q1 \: q2}{9} \\ 0.075 = {10}^{9} q1 \: q2 \\ 0.075 \times {10}^{ - 9} = \: q1 \: q2 \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: (1) \\ \\ now \: \\ \\ q1 \: + \: q2 = 20 \times {10}^{ - 6} \: \\ q1 = 20 \times {10}^{ - 6} - q2 \: \: \: \: \: \: \: \: \: put \: in \: (1) \\ \\ 0.075 \times {10}^{ - 9} = (20 \times {10}^{ - 6} - q2) \: q2$

Solve this equation and find q2 then put value of q2 in the eq.

q1+q2=20 × 10^-6

And find q1

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Answer 2

Answe

Explanation:

Two point charge Q1and Q2 and Q3