Two point charges, Q1 and Q2, are located a distance 0.20 meter apart, as shown above. Charge Q1 = +8.0μC.
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a. E = kQ/r2 and since the field is zero E1+ E2 = 0 giving k(Q1/r12 + Q2/r22) = 0
This gives the magnitude of Q2 = Q1(r22/r12) = 2μC and since the fields must point inopposite directions from each charge at point P, Q2 must be negative.
b. F = kQ1Q2/r2 = 3.6 N to the right (they attract)
c. U = kQ1Q2/r = -0.72 J
d. between the charges we have a distance from Q1 of x and from Q2 of (0.2 m – x)
V = kQ1.x + kQ2/(0.2 m – x) = 0, solving for x gives x = 0.16 m
e. W = qΔV where ΔV = V∞ – VR = 0 so W = 0
This gives the magnitude of Q2 = Q1(r22/r12) = 2μC and since the fields must point inopposite directions from each charge at point P, Q2 must be negative.
b. F = kQ1Q2/r2 = 3.6 N to the right (they attract)
c. U = kQ1Q2/r = -0.72 J
d. between the charges we have a distance from Q1 of x and from Q2 of (0.2 m – x)
V = kQ1.x + kQ2/(0.2 m – x) = 0, solving for x gives x = 0.16 m
e. W = qΔV where ΔV = V∞ – VR = 0 so W = 0
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