Question

Two point charges Q1 and Q2 lie along a line at a distance from each other.

Figure shows the potential varation along the line of charges. At which of the

points 1, 2 and 3 is the electric field zero? Give reason to support your answer.

V-Potential
r-Distance​

Answer 1

Answer:

Explanation:

1 both field are opposite and equal at point p

2 both charges are opposite sing but Not be equal or equal because it depends on point p is at centre or not

Answer 2

Answer:

The electric field vector is zero at point 3. As-dV/dr = E, the negative of the slope of V verus r curve represents the com ponent of electric field along r. Slope of curve is zero only at 3.

Near positive charge, net potential is positive and near a negative charge net potential is negative. Thus, charge Q, is positive and 2, negative. From the graph, it can be seen that net potential due to the two charges is positive everywhere in the region left of charge 2,. Therefore, the magnitude of potential due to charge, is greater than that due to Q. Therefore, the absolute value of charge 2, is greater than that of Q. Secondly, point 1, where potential due to two charges is zero, is nearer to charge Q, thereby implying that 2, has greater absolute value. Also, potential is zero at 2, which is toward right of Q,, as we know that potential is zero at an outside point toward the side of charge smaller in magnitude.

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